Sire Roan Black on dam Smoky Cream
In this article, we will explore the genetic possibilities of coat colors for the crossing between a stallion Roan Black and a mare Smoky Cream. Equine genetics is a universe of combinations where dominant and recessive alleles determine the final coat of each individual.
On one side, we have the stallion Roan Black. Genetically, it presents the base genotype E/_ a/a Rn/n. The (Rn) gene acts on the base coat by distributing white hairs throughout the body, giving it a roan appearance. The head and legs retain the original base color tones. This coat is based on Black.
On the other side, the mare Smoky Cream contributes with its genetics based on E/_ a/a Cr/Cr. Very pale coat with yellowish highlights, resulting from double dilution of the cream gene over the black base.
Quando combinamos esses códigos genéticos, criamos uma matriz de probabilidades. É importante lembrar que o resultado visual (fenótipo) muitas vezes esconde genes recessivos que podem pular uma geração.
The Genotypes Involved
For a horse to have the coat Roan Black. it carries specific gene combinations. The possible genotypes for the sire include variants such as: E/e a/a Rn/n, E/e a/a Rn/Rn, E/E a/a Rn/n, E/E a/a Rn/Rn.
As for the dam, being Smoky Cream, may present in its DNA the alleles: E/e a/a Cr/Cr, E/E a/a Cr/Cr.
Understanding the Alleles
To understand the result of this crossing, note the gene sets at play:
- E/ (Extension - Dominant): The Extension gene controls eumelanin (black) production. At least one E allele allows the horse to have black hairs.
- a/a (Non-Agouti - Recessive): Allows black pigment to spread uniformly across the body. Essential for Solid Black (if E/).
- Cr/Cr (Double Cream): Maximum dilution. Pink skin, blue eyes (e.g. Cremello, Perlino).
- Rn/ (Roan - Rosilho): Mixes white hairs throughout the body, keeping head and extremities in the original color.
Calculated Probabilities
Being the sire Roan Black with genotype (E/e a/a Rn/n), it transmits the (E) allele (black factor) to 50% and the (e) allele (red factor) to the other 50% and transmits the (a) allele to 100% of offspring, allowing black to spread in homozygosis (if Extension is present) and has a 50% chance of transmitting the Roan allele (Rn).
Being the sire Roan Black with genotype (E/e a/a Rn/Rn), it transmits the (E) allele (black factor) to 50% and the (e) allele (red factor) to the other 50% and transmits the (a) allele to 100% of offspring, allowing black to spread in homozygosis (if Extension is present) and always transmits the Roan allele (Rn).
Being the sire Roan Black with genotype (E/E a/a Rn/n), it transmits the (E) allele to 100% of offspring, enabling black pigment production (eumelanin) and transmits the (a) allele to 100% of offspring, allowing black to spread in homozygosis (if Extension is present) and has a 50% chance of transmitting the Roan allele (Rn).
Being the sire Roan Black with genotype (E/E a/a Rn/Rn), it transmits the (E) allele to 100% of offspring, enabling black pigment production (eumelanin) and transmits the (a) allele to 100% of offspring, allowing black to spread in homozygosis (if Extension is present) and always transmits the Roan allele (Rn).
Being the dam Smoky Cream with genotype (E/e a/a Cr/Cr), it transmits the (E) allele (black factor) to 50% and the (e) allele (red factor) to the other 50% and transmits the (a) allele to 100% of offspring, allowing black to spread in homozygosis (if Extension is present) and always transmits the Cream dilution allele (Cr).
Being the dam Smoky Cream with genotype (E/E a/a Cr/Cr), it transmits the (E) allele to 100% of offspring, enabling black pigment production (eumelanin) and transmits the (a) allele to 100% of offspring, allowing black to spread in homozygosis (if Extension is present) and always transmits the Cream dilution allele (Cr).
Based on a standard scenario, the statistical chances for foals from this crossing are:
Roan Smoky BlackOpen Coat ➜ 43,9%
Smoky BlackOpen Coat ➜ 43,9%
Roan PalominoOpen Coat ➜ 6,1%
PalominoOpen Coat ➜ 6,1%
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